- #1

- 4

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and the lower sum is mi = 0+(i-1)(2/n)

So the question is why is it (i-1) for the lower sum and only i for the upper sum?

Any help is highly appreciated! ^_^

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- Thread starter sukisyo
- Start date

- #1

- 4

- 0

and the lower sum is mi = 0+(i-1)(2/n)

So the question is why is it (i-1) for the lower sum and only i for the upper sum?

Any help is highly appreciated! ^_^

- #2

- 60

- 0

State the entire problem.

- #3

- 4

- 0

Set in the interval [0,2], it asks me to explain why I need to have i minus 1 in finding the lower sum (the left endpoints) where as in finding the upper sum, it is just i.

- #4

- 60

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Lower/Upper sum of what?

- #5

- 4

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ok. here is everything. i don't know if it helps.

Find the upper and lower sum for the region bounded by the graphy of f(x) = x^2 and x-axis between x=0 and x=2. To begin, partition the interval [0,2] into n sublevels, each of length (triangle X) = (b-a)/n = (2-0)/n = 2/n

Left endpoints:

https://www.physicsforums.com/latex_images/39/394830-1.png [Broken]

Right endpoints:

https://www.physicsforums.com/latex_images/39/394830-3.png [Broken]

QUESTION: why does the equation need (i-1) for finding the left endpoints when it only needs i in finding the right endpoints?

Find the upper and lower sum for the region bounded by the graphy of f(x) = x^2 and x-axis between x=0 and x=2. To begin, partition the interval [0,2] into n sublevels, each of length (triangle X) = (b-a)/n = (2-0)/n = 2/n

Left endpoints:

https://www.physicsforums.com/latex_images/39/394830-1.png [Broken]

Right endpoints:

https://www.physicsforums.com/latex_images/39/394830-3.png [Broken]

QUESTION: why does the equation need (i-1) for finding the left endpoints when it only needs i in finding the right endpoints?

Last edited by a moderator:

- #6

- 84

- 0

First, those are the positions of the left/right endpoints, not the upper/lower sums.

Now, think about this, is 0 a left or a right endpoint? and 2?

What happens when i=1 and i=n? (remeber that i=1,2,...n)

Last edited:

- #7

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So i asked a friend and she said:

"Mi and mi are the right and left endpoints so to find its exact value, we take the i (which names the specific interval) and multiply it by the value of the subintervals (delta x)and since the area of the subinterval is height times width, then height is found by f(mi) or f(Mi) and width is delta x. mi is (i-1) because lets say Mi is at i

then the left endpoint (mi) is the right endpoint of the previous interval so that is why it is i-1."

She isn't really sure about her answer but i can't think of anything else so i'm just going to accept it. Also if this is the answer, it's like common sense, so i'm going to be feeling really stupid.

Thanks for all your help though. I really appreciate your time and hard effort in attemping to free me from my dilemma. ^_^

- #8

HallsofIvy

Science Advisor

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